(3-x)^2+8(3-x)=-12

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Solution for (3-x)^2+8(3-x)=-12 equation: 



(3-x)^2+8(3-x)=-12

We move all terms to the left:

(3-x)^2+8(3-x)-(-12)=0

We add all the numbers together, and all the variables

(-1x+3)^2+8(-1x+3)-(-12)=0

We add all the numbers together, and all the variables

(-1x+3)^2+8(-1x+3)+12=0

We multiply parentheses

(-1x+3)^2-8x+24+12=0

We add all the numbers together, and all the variables

-8x+(-1x+3)^2+36=0

We move all terms containing x to the left, all other terms to the right

-8x+(-1x+3)^2=-36

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